(7x+5)(2x^2-17x-9)=0

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Solution for (7x+5)(2x^2-17x-9)=0 equation: 


Simplifying
(7x + 5)(2x2 + -17x + -9) = 0

Reorder the terms:
(5 + 7x)(2x2 + -17x + -9) = 0

Reorder the terms:
(5 + 7x)(-9 + -17x + 2x2) = 0

Multiply (5 + 7x) * (-9 + -17x + 2x2)
(5(-9 + -17x + 2x2) + 7x * (-9 + -17x + 2x2)) = 0
((-9 * 5 + -17x * 5 + 2x2 * 5) + 7x * (-9 + -17x + 2x2)) = 0
((-45 + -85x + 10x2) + 7x * (-9 + -17x + 2x2)) = 0
(-45 + -85x + 10x2 + (-9 * 7x + -17x * 7x + 2x2 * 7x)) = 0
(-45 + -85x + 10x2 + (-63x + -119x2 + 14x3)) = 0

Reorder the terms:
(-45 + -85x + -63x + 10x2 + -119x2 + 14x3) = 0

Combine like terms: -85x + -63x = -148x
(-45 + -148x + 10x2 + -119x2 + 14x3) = 0

Combine like terms: 10x2 + -119x2 = -109x2
(-45 + -148x + -109x2 + 14x3) = 0

Solving
-45 + -148x + -109x2 + 14x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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